09/02/23 12:05:02
@DMCC @lecture @py7002
- For example 4.1. v rms is 100<0.
- I_R = 10<0
- I_L = 26.93A<90
- More current going through inductor. I = R_R + I_L = 10 -j26.93.
- Current flowing is 28A, that gives 10A to resistor another value to inductor, but based on rms..
- P = 1000W.
- Reactive power is 2.6. Power factor is 0.35.
- Reactive compensation, adding a capacitor so that inductor power (which has some sort of feedback power effect) can be allowed for.
- Not always obvious whats the load and the source.
- 4.2: S = -500(P) + 8666j(Q). In this case the negative power is dumping power into source, but providing reactive power. Example might be inertia of motor, shut off producing a back emf.
- 4.3. d) S = 2.9MVA, V = 10.02KV. e)
- His teaching style is painful.